Mathematics
Mathematics, 12.06.2020 02:57, 3peak101

1. Use limit comparison test to determine whether the series converges or diverges: Σ[infinity]_n=1 n^2 + 1 / 2n^3 - 1

2. Use limit comparison test to determine whether the series converges or diverges:

Σ[infinity]_n = 1 n / √n^5 + 5

3. Use direct comparison test to determine whether the series converges or diverges:

Σ[infinity]_n = 1 4 + 3^n / 2^n

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Answers: 2

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