Joshua ate 2/6 of his sandwich in the afternoon and 2/6 more for a snack later that day. How much of Joshua’s sandwich is left?

1/3 left

Step-by-step explanation:

The total sandwich is 1 or in fraction form 6/6

He ate 2/6

6/6 -2/6 = 4/6

Then he ate 2/6 more

4/6 -2/6 = 2/6

He has 2/6 left

Simplifying

2/6 =1/3

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)