Using the definition of the derivative, find f prime (x ). Then find f prime (1 ), f prime (2 ), and f prime (3 )when the derivative exists.

Step-by-step explanation:

We need the function f(x) to be able to determine the required.

Suppose we were given a function

f(x) = y

f'(x) represents the first derivative of the function f(x) = y.

f'(1) represents the value of the first derivative of the function f(x) = y after replacing x by 1.

f'(5) represents the value of the first derivative of the function f(x) = y after replacing x by 5.

Example: Suppose f(x) = x² + 3x, find

f'(x), f'(1), and f'(5).

f'(x) = 2x + 3

f'(1) = 2(1) + 3 = 5

f'(5) = 2(5) + 3 = 13

u what ?

step-by-step explanation:

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47