Mathematics, 10.06.2020 17:57, leo4687

Simplify. x+5/x^2+6x+5 1/x+1; where x ≠ -1
1/x+1; where x ≠ -1,-5
1/x-5; where x ≠ 5
X-5

Answers: 3

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Simplify. x+5/x^2+6x+5 1/x+1; where x ≠ -1
1/x+1; where x ≠ -1,-5
1/x-5; where x ≠ 5

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Simplify. x+5/x^2+6x+5 1/x+1; where x ≠ -1 1/x+1; where x ≠ -1,-5 1/x-5; where x ≠ 5 X-5

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Other questions on the subject: Mathematics

Questions in other subjects:

Simplify. x+5/x^2+6x+5 1/x+1; where x ≠ -1
1/x+1; where x ≠ -1,-5
1/x-5; where x ≠ 5
X-5