What is the product? (5 r + 2)(3 r minus 4)

15 r squared + 8
15 r squared minus 8
15 r squared + 14 r minus 8
15 r squared minus 14 r minus 8

Hey!!

Solution,

(5r+2)(3r-4)

= 5r(3r-4)+2(3r-4)

= 15r^2-20r+6r-8

= 15r^2-14r-8

So the right answer is 15 r squared minus 14 r minus 8

Hope it helps

Good luck on your assignment

answer: what

step-by-step explanation:

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine