Hashim had some money. His sister had $75.10. after Hashim gave his mother $28, he had $15.20 less than his sister. How much did he have at first? ps: this is for grade 4 maths. can i get a simplified working for this question? thank you!

Step-by-step explanation:

Given:

Hashim had some money.

His sister had $75.10.

After Hashim gave his mother $28, he had $15.20 less than his sister.

Solve for:

The original amount of money Hashim had.

Step 1: Define the problem

Let's say, Hashim had an original amount of money, we call it A

Hashim gave his mother 28$, then his remaining amount of money is A - 28

Hashim's remaining amount of money is 15.2$ less than his sister's amount of money: 75.10$.

Hence, the relation between Hashim's remaining amount of money and his sister's amount of money is expressed as:

A - 28 = 75.1 - 15.2

Step 2: Solve the equation to get A

A - 28 = 75.1 - 15.2

Let's first perform the subtraction on the right side of equation:

A - 28 = 59.9

Now, we move all of numbers to the right side of equation, except A:

(please notice that the sign of 28 will be changed from - to +)

A = 59.9 + 28

Let's perform the addition on the right side of equation to get A:

A = 87.9$

=> Hashim's original amount of money: A = 87.9$

Hope this helps!

:)

step-by-step explanation:

two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.

the answer is a and d