Can anyone please help me with this?

point - slope form: y+1 =2(x+2)

slop - intercept form:  y =2x +3

standard form : 2x -y = -3 or -2x+y = 3

Step-by-step explanation:

find slope from given points using slope formula y₂ -y₁ / x₂ -x₁

slope m =5-(-1)/1-(-2) =6/3 =2

point - slope form is y - y₁ =m (x - x₁) where x₁ and y₁ are coordinates of one of the given points so

y - (-1) = 2(x -(-2))

y+1 =2(x+2)

slop - intercept form is y =mx +b where m is a slope and b is y intercept

now if you rearrange y+1 =2(x+2) as y =......

y+1 =2(x+2) → y+1=2x+4 → y = 2x+4-1 → y =2x +3

standard form is Ax +By = C where A,B,C are numbers; then by rearranging the equation again, it will be

2x -y = -3

graphing is done by using  slop - intercept form:  y =2x +3

pick 2 points and draw the line; use given points

17.08

correct me if i am wrong.