Find the equation of the line, in slope- intercept form, that passes through the point
(-3. 2) and has slope 3.
of the equation for

y= 3x +11

Step-by-step explanation:

slope-intercept form:

y= mx+c, where m is the gradient and c is the y-intercept.

Given that the slope is 3, m=3

substitute m=3 into the equation:

y= 3x +c

To find the value of c, substitute a coordinate.

When x= -3, y=2,

2= 3(-3) +c

c -9= 2

c= 9 +2 (+9 on both sides)

c= 11 (simplify)

Thus, the equation of the line is y= 3x +11.

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

answer: the first graph

step-by-step explanation: