Square root of x²-6x+9 if x is greater than or equal 3

x-3

Step-by-step explanation:

x²-6x+9 is equal to (x-3)²

The square root of any term that is positive is equal to the absolute value of the term. If x is greater or equal to 3, it makes the term positive.

So the root of x²-6x+9 is x-3  

answer: was that a question or answer?

step-by-step explanation:

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation: