What is the equation, in slope-intercept form, of the line that is perpendicular to the line y-4 = -(x - 6) and passes through the point (-2, -2)?
o y = x - 10
0 y = x + 10
o y = 2 X-1
O y = x + 1

y = 3/2x - 1

Step-by-step explanation:

Slope intercept form = y = mx + b

m = slope of the line = -2/3

y = -2/3x + b

Plug in (-2, -2) and the perpendicular line is

y = 3/2x - 1

You are welcome and don't for get to click THANKS

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

a) justify

step-by-step explanation:

justifying is just part of everyday life. justify kind of means proof so i think the answer is a) justify.