Clara goes mini golfing. She pays $7.50 for an admission ticket and $6.25 for each round she golfs. The total amount Clara pays for admission and the number of rounds she golfs is $26.25. Which equation can be used to determine the number of rounds, x, that Clara golfs? 6.25x + 7.50 = 26.25

6.25x - 7.50 = 26.25

7.50x + 6.25 = 26.25

7.50x - 6.25 = 26.25

6.25x + 7.50 = 26.25

Step-by-step explanation:

Given that

The admission fee is = $7.50

Each round costs = $6.25

Total money Clara paid = $26.25

The computation of equation can be used to determine the number of rounds, x, that Clara golfs is shown below:-

we assume the number of rounds = x

Here, We can denote this equation in the following form

Therefore with the help of above equation we can now find out the x value

So, Clara played 3 rounds of golf.

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)