15 POINTS!! PLEASE HELP The equation of line WX is 2x + y = −5. What is the equation of a line perpendicular to line WX in slope-intercept form that contains point (−1, −2)?

y = one half x + three halves
y = negative one halfx + three halves
y = one half x − three halves
y = negative one halfx − three halves

y = 1/2x - 1

Step-by-step explanation:

The easiest was you do this is to first rearrange the equation into slope-intercept form (y = mx + b).  After rearranging, you can find the slope (m).

2x + y = -5

y = -2x - 5

The slope is -2.  Since the line we are trying to find is perpendicular, find the inverse and multiply it by -1.

-2  =>  1/2

Now use the point-intercept form to find the new equation.  Use the slope (1/2) and the given point (-1, -2).

y - y₁ = m(x - x₁)

y - (-2) = 1/2(x - (-2))

y + 2 = 1/2(x + 2)

y + 2 = 1/2x + 1

y = 1/2x - 1

The equation of the line perpendicular to line WX is  y = 1/2x - 1.

the answer is b; false. 2 dimensional things are a lot more different from 3 dimensional things.

i hope this ! : d

"stay and stay proud! " - zalgo

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.