The mean of the data set {9, 5, y, 2, x } is twice the data set {8, x, 4, 1, 3}. What is (y-x)^2?

256

Step-by-step explanation:

To calculate the mean, we simply divide the sum of the values by the count.

For the first set, the mean is as follows;

(9 + 5 + 2 + y + x)/5 = (x + y + 16)/5

For the second set;

(8 + x + 4 + 1 + 3)/5 = (16 + x)/5

Since both are divided by 5, we can eliminate it

Mean of first set is twice the second

This means that;

x + y + 16 = 2(16 + x)

x + y + 16 = 32 + 2x

y = 32-16+2x-x

y = 16 + x

Now we want to calculate

(y-x)^2

substitute the value of y here

(16+x-x)^2

= 16^2 = 256

c

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a