In circle T with m ∠ S V U = 5 6 ∘ m∠SVU=56 ∘ , find the angle measure of minor arc ⌢ . SU ⌢

Given:

m∠NRQ = 60°

To find:

The angle measure of minor arc NQ

Solution:

The inscribed angle is half of the intercepted arc.

Multiply by 2 on both sides.

Substitute m∠NRQ = 60°.

The measure of minor arc NQ is 120°.

your answer would be 10x - 1

step-by-step explanation:

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