PLEASE HELP! The following are the last 10 run scores Colin got in cricket: 31, 10, 26, 16, 28, 31, 9, 11, 8, 1 a) Work out Colin's mean score. b) Colin plays cricket again on Sunday. He gets 27 runs. What is his new mean score? Give your answers as decimals.

Colin's mean score = 17.10

The new mean is 18.00

Step-by-step explanation:

Given scores: 31, 10, 26, 16, 28, 31, 9, 11, 8, 1

number of terms: 10

mean is calculated by given formula = sum of all the data set/ number of terms in the data set.

mean for the 10 scores = (31+ 10+ 26+ 16+ 28+ 31+ 9+ 11+ 8+ 1 )/10

                                       = 171/10 = 17.1

Colin's mean score = 17.10

runs scored by Colin in 11th match = 27

number of terms: 11

new mean = new sum /number of terms

new mean = (old sum score + 27)/11 = (171+27)/11

new mean = 198/11 = 18

The new mean is 18.00

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: