Mathematics, 09.06.2020 21:57, abelsoto

The graph of f(x) = ax^2 opens upward and is narrower than the graph of g(x) = x^2 . Which of the following could be the value of a? A. -0.5

B. 6

C. 0.25

D. -2

Answers: 2

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Answers

answered: layla07

Following are the solution to the graph function:

Given:

Graph function:

$\to f(x)=ax^2\\\\\to g(x)=x^2\\\\$

Solution:

It is assumed that its graph of f(x)=ax^2

is narrower more expands upwards than the graph of g(x)=x^2

.The graph of f(x)= ax^2

expands upward, suggesting that the g(x)=x^2

coefficient must be positive.Since the graph of f(x)=ax^2

is thinner than that of the graph of g(x)=x^2

, it implies that the coefficient of x^2

has to be between 0 to 1, i.e.

.Only 0.25 is a positive number with just an absolute value between 0 and 1 among the available alternatives.

Therefore, the final answer is "Option C".

Learn more about the graph:

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answered: ravenalionna115

Option C.

Step-by-step explanation:

The given functions are

f(x)=ax^2

g(x)=x^2

It is given that the graph of f(x)=ax^2 opens upward and is narrower than the graph of g(x)=x^2 .

Graph of f(x)=ax^2 opens upward, it means coefficient of x^2 must be positive.

Graph of f(x)=ax^2 is narrower than the graph of g(x)=x^2 , it means coefficient of x^2 must lies between 0 to 1, i.e., .

From the given options, only 0.25 is a positive number whose absolute value lies in between 0 to 1.

Therefore, the correct option is C.

answered: Guest

b. the decimal could be two-tenths.

step-by-step explanation:

answered: Guest

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

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The graph of f(x) = ax^2 opens upward and is narrower than the graph of g(x) = x^2 . Which of the fo...