Glen says, when someone picks a positive integer, and then writes down a sum of all integers from one to the integer that was picked and then adds all the integers back down to one, the
sum will be the square of the integer that was picked.
For example:
Pick 5, 1+2+3+4+5+4+3+2+1=52
Pick 7, 1+2+3+4+5+6+7+6+5+4+3+2+1=72
Will this always work for any positive integer?
Why?

853.3

step-by-step explanation:

central angle of a triangle has the same measure as its intercepted arc.

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.