What is the solution to the inequality 1 and two-thirds greater-than-or-equal-to r minus StartFraction 7 over 12 EndFraction question mark r less-than-or-equal-to negative 2 and one-fourth
r less-than-or-equal-to 2 and one-fourth
r greater-than-or-equal-to 2 and one-fourth
r greater-than-or-equal-to negative 2 and one-fourth

entering that problem on the tube might get you an answer

he will have 300 because he is really broke and 300 is in his imangine

step-by-step explanation: he ehe heh step by the thy

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

4y - 6 + y^2 - 9 = y^2 + 4y - 15

y^2 term

terms

- terms

total of 3 terms when simplified

step-by-step explanation: