Which relationships have the same constant of proportionality between y
yy and
x
xx as the equation
y
=
1
2
x
y=
2
1

xy, equals, start fraction, 1, divided by, 2, end fraction, x?
Choose 3 answers:
Choose 3 answers:

(Choice A)
A
6
y
=
3
x
6y=3x6, y, equals, 3, x

(Choice B)
B

2
2
4
4
6
6
8
8
2
2
4
4
6
6
8
8
y
y
x
x

(Choice C)
C

2
2
4
4
6
6
8
8
2
2
4
4
6
6
8
8
y
y
x
x

(Choice D)
D
x
xx
y
yy
2
22
1
11
3
33
2.5
2.52, point, 5
4
44
3
33

(Choice E)
E
x
xx
y
yy
4
44
2
22
5
55
2.5
2.52, point, 5
10
1010
5
55

A, B and E

Step-by-step explanation:

y = (1/2)x has the form y = kx, with k = 1/2, its constant of proportionality.

A) 6y = 3x

y = (3/6)x

y = (1/2)x

B) We have to find the  slope of the line. Using points (0,0) and (4, 2)

slope = (2 - 0)/(4 - 0) = 1/2

C) We have to find the  slope of the line. Using points (0,0) and (2, 4)

slope = (4 - 0)/(2 - 0) = 2

D) We have to find the  slope of the line. Using points (2,1) and (4, 3)

slope = (3 - 1)/(4 - 2) = 1

E) We have to find the  slope of the line. Using points (4,2) and (10, 5)

slope = (5 - 2)/(10 - 4) = 1/2

where is abdul's work? don't see that anywhere posted : /

step-by-step explanation: