How do you factor the trinomial 3x^2+18x-21?

(3)(x+7)(x-1)

Step-by-step explanation:

3x^2+18x-21

Let's start by taking 3 out of the equation.

3(x^2+6x-7)

Now, when we factor, we need to find two numbers that add up to 6 and multiply to -7.

The numbers would be 7 and -1.

So the factored form of this would be:

(3)(x+7)(x-1)

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -

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