Line k has an equation of y = -2x - 6. Perpendicular to line k is line I, which passes through the point (3, 6). What is the equation of line l?
Write the equation in slope-intercept form. Write the numbers in the equation as proper
fractions, improper fractions, or integers.

y = x/2 +9/2

Step-by-step explanation:

y = -2x - 6.

The equation of the line perpendicular to the above equation has a slope 1/2

The equation of a slope is

y2-y1/x2-x1 = 1/2

To form an equation of the line we chose a point that lies on the graph which is perpendicular to y = -2x - 6 and an arbitrary point (x,y)

A point is given us already and that point is (3, 6).

Tie all together to compute the slope we have;

y-6/x-3 = 1/2

2(y-6) = x-3

2y-12= x-3

2y = x-3+12

2y= x+9

Dividing through by 2 we have

y = x/2 +9/2

y = x/2 + 4.5

555.99.

step-by-step explanation:

hope this

no he doesnt because "-16' is negatiive

step-by-step explanation: