A média aritmética entre um inteiro positivo x e o seu sucessor é maior que 5. Quais são os possíveis valores de x?

Any value greater than 5:

x > 5

Step-by-step explanation:

The average of two numbers 'a' and 'b' is given by the formula:

Average = (a + b)/2

If the average between x and its successor (that is, x+1) is greater than 5, we have that:

(x + (x+1)) / 2 > 5

x + x + 1 > 10

2x > 9

x > 4.5

The value of x is an integer number, so x can be any number greater than 5:

x > 5

it would be 6xy and -16xy.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)