The line plots show the number of minutes two different age groups of teenagers spent online the previous week. Select from the drop-down menus to complete each statement.

1) The range is _.
a) is greater for data set one (13-15-year-olds)
b) is greater for data set two (16 to 18-year-olds)
c) is the same for both sets of data

2) The mean _.
a) is the same for both sets of data
b) is greater for data set one (13-15-year-olds)
c) is greater for data set two (16 to 18-year-olds)

Step-by-step explanation:

13-15 year olds:

Range: 13

Mean: 27.4

16-18 year olds:

Range:24

Mean: 28.05

Therefore,

1) the range is greater for set two

2) the mean is greater for set two as well

1. B

2. C

Step-by-step explanation:

dhhghghghhrhbb it 5

d

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!