John and Trey both leave the coffee shop at the same time, but in opposite directions. If Trey travels 7 mph faster than John and after 5 hours they are 85 miles apart, how fast is each traveling? John is traveling mph

Trey is traveling mph

John is traveling 5 mph

Trey is traveling 12 mph

Step-by-step explanation:

we will concept of speed distance and time where

distance = speed * time

Let the speed of john be x miles per hour

if, Trey travels 7 mph faster than John

then speed of trey = (x+7) miles per hour

Time of travel for both of them  = 5 hours

distance traveled by john in 5 hours =  x* 5 = 5x miles

distance traveled by john in 5 hours =  (x+7) * 5 = (5x + 35)miles

total distance covered by them = 5x miles + (5x + 35)miles = (10x+35) miles

it is given that after 5 hours they were 85 miles apart, thus the distance above calculated should be equal to 85 miles

10x+35 = 85

=>10x = 85 -35

=> 10x = 50

=> x = 50/10

=> x = 5

Thus, speed of john is 5 miles per hour

speed of Trey is: x+7= 5 + 7 = 12  miles per hour

sine

step-by-step explanation:

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol