Consider a problem classified by 3 rows and 2 columns containing 350 observations. The table is described in the figure below and has the following cell counts: A-196, B-36, C=0, D=90, E=21, F=7. Let event S denote an item that occurs in row 1 and event T denote an item that occurs in column 1. Find P(T|S) Colu mnColum A D BE row row2 ww3 F F PTIS) Fiel 0.92 0.8171 0.8448 0.56 0.6629

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

for this case we must apply distributive property to the following expression:

the distributive property states that:

then, when applying the property we have to multiply the -2 for each term within the parenthesis: