10. A school is trying to schedule periods of Chemistry and Algebra II. They find that a total of 386 students are taking either one or both of
the two courses. If 298 students signed up for Algebra II and 328 have
signed up for Chemistry, what would be the probability that a student
chosen at random from the 386 will be signed up for both of the
courses? Round your answer to the nearest whole number percent.

~62%

Step-by-step explanation:

Let n(A) be the number of students signed up for Algebra II.

Given that n(A) = 298

Let n(B) be the number of students signed up for Chemistry.

Given that n(B) = 328

n(A B) will be the number of students who have signed up for either one or both of two subjects.

n(A B) = 386

Formula for n(A B):

n(A B) = n(A) + n(B) - n(A B)

Where n(A B) is the number of students signed up for both the courses.

Putting the values in the formula above:

386 = 298 + 328 - n(A B)

n(A B) = 240

Formula for Probability of an event E:

Hence, the required probability is ~62%

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )