Ellen saved $2000 and she spent 10% of it to buy a bike. Kim saved 8% more than that of Ellen's left savings. If Lisa saved 60% as much as Kim, how much money did Lisa save?

Lis saved $1166.4 .

Step-by-step explanation:

Given , Ellen saved $2000 and she spent 10% of it to buy a bike.

Then, Ellen's left saving = saved amount - 10% of  (saved amount)

= $2000 - 0.10 x $2000 [We convert perecntage to decimal by diving it by 100]

= $2000 - $200

= $1800

So, Ellen's left saving= $1800

Also, Kim saved 8% more than that of Ellen's left savings.

Kim's Saving = Ellen's left saving + 8% of (Ellen's left saving)

= $1800  + (0.08) x ($1800) [We convert perecntage to decimal by diving it by 100]

= $1800 +  $144

i.e. Kim's Saving= $1944

If Lisa saved 60% as much as Kim, then Lisa's saving  = 60% of (Kim's Saving)

= (0.60) x ($1944) [We convert perecntage to decimal by diving it by 100]

i.e. Lisa's saving = $1166.4

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)