Suppose an actual census showed that 20% of the households in Michigan have incomes in excess of $60,000. Assume that a random sample of 500 households in Michigan is taken. Then, the standard error of the sampling distribution of sample proportion of households who have incomes in excess of $60,000 will be:

0.0179

Step-by-step explanation:

We know that , the  standard error of the sampling distribution of sample proportion (p) is given by :-

where , n= sample size

Let p be the  proportion of households who have incomes in excess of $60,000 .

As per given , we have

p= 20% = 0.20

n= 500

Then,

Hence, the standard error of the sampling distribution of sample proportion of households who have incomes in excess of $60,000 is 0.0179.

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!