Find the equation of the straight line passing through the point (3,5) which is perpendicular to the line y=3x+2

y=-1/3x+6 .Hope this helps

3y = -x + 18

Step-by-step explanation:

Given the equation y = 3x + 2;

By comparison with the general equation

y = mx + C ; where m is the slope

We see that m = 3

Now for a perpendicular line and it's slope is -1/m = -1/3 and let it be M2

But the new slope cuts across points (3,5) .

It means M2 = y - 5/ x-3

-1/3 = y-5/ x-3

-1(x-3) = 3(y-5)

-x +3 = 3y -15

3y = -x + 18

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation: