A circle is centered at O(0,0)O(0,0)O, left parenthesis, 0, comma, 0, right parenthesis and has a radius of \sqrt{29} 29



square root of, 29, end square root.

Where does the point T(5,-2)T(5,−2)T, left parenthesis, 5, comma, minus, 2, right parenthesis lie?

Point T is on the circle

Step-by-step explanation:

To check where the point lies, we need to find its distance to the center of the circle.

The distance between two points (x1, y1) and (x2, y2) is given by:

If the first point is O(0,0) and the second is T(5, -2), we have:

The distance between the points is equal the radius of the circle, that means the point T is on the circle.

idk

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.