Find the exact values of sin 2x and cos 2x for cos x=3/7 on the interval 0 *view photo for choices*

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

include a picture of the drawing in order for me to

step-by-step explanation:

what’s the question?