There are 4 green marbles, 5 red marbles, and 6 blue marbles in a bag. Find the probability of drawing a red marble, replacing it back in the bag, and then drawing a second red marble *

1/9

Step-by-step explanation:

4 green marbles, 5 red marbles, and 6 blue marbles in a bag = 15 marbles

P(red)= number of red/ total = 5/15 = 1/3

Put it back in the bag

4 green marbles, 5 red marbles, and 6 blue marbles in a bag = 15 marbles

P (red)= number of red/ total = 5/15 = 1/3

P(red, replace, red) = P(red) * P(red) = 1/3*1/3 = 1/9

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.