Three polynomials are factored below, but some coefficients and constants are missing. All of the missing values of a, b, c, and d are integers 1. x^2-2x-15=(ax+b)(cx+d) 2. 2x^-6x-36x=2x(ax+b)(cx+d) 3. 4x^2+10x+4=(ax+b)(cx+d) . Fill in the table with the missing values of a, b, c, and d.

Step-by-step explanation:

Obviously, factors can be written in any order. So, there are multiple answers to this question.

1. x^2 -2x -15 = (x -5)(x +3) . . . . (a, b, c, d) = (1, -5, 1, 3)

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2. 2x^2 -6x -36 = 2(x^2 -3x -18) = 2(x -6)(x +3) . . . . (a, b, c, d) = (2, -12, 1, 3)

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3. 4x^2 +10x +4 = 2(2x^2 +5x +2) = 2(2x +1)(x +2) . . . . (a, b, c, d) = (4, 2, 1, 2)

yes

yes yes yes

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2