Below is a two-column proof incorrectly proving that the three angles of ΔPQR add up to 180°: StatementsReasons
∠QRY ≅ ∠PQRAlternate Interior Angles Theorem
Draw line ZY parallel to segment PQConstruction
m∠ZRP + m∠PRQ + m∠QRY = m∠ZRYAngle Addition Postulate
∠ZRP ≅ ∠RPQAlternate Interior Angles Theorem
m∠RPQ + m∠PRQ + m∠PQR = m∠ZRYSubstitution
m∠ZRY = 180°Definition of a Straight Angle
m∠RPQ + m∠PRQ + m∠PQR = 180°Substitution

Which statement will accurately correct the two-column proof?
The measure of angle ZRY equals 180° by definition of supplementary angles.
Angles QRY and PQR should be proven congruent after the construction of line ZY.
The three angles of ΔPQR equal 180° according to the Transitive Property of Equality.
Line ZY should be drawn parallel to segment QR.

details

step-by-step explanation:

the answer is stop cheating on things stoopid

step-by-step explanation:

im eatin up the 44

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.