Pulse rates of adult females are listed in Data Set 1 "Body Data" in Appendix B. The lowest pulse rate is 36 beats per minute, the mean of the listed pulse rates is x = 74.0 beats per minute, and their standard deviation is s = 12.5 beats per minute. a. What is the difference between the pulse rate of 36 beats per minute and the mean pulse rate of the females? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the pulse rate of 36 beats per minutes to a z score. d. If we consider pulse rates that convert to z scores between -2 and 2 to be neither significantly low nor significantly high, is the pulse rate of 36 beats per minute significant?

Step-by-step explanation:

Hello!

The variable of interest is

X: pulse rate of a female adult. (beats/min)

Mean X[bar]= 74.0 beats/min

Standard deviation S= 12.5 beats/min

The lowest pulse rate is 36 beats/min

a)

The difference between the lowest pulse rate and the mean pulse for females is: 36 - 74= -38 beats/min

b)

To calculate how many standard deviations a value of the variable is from the mean, you have to subtract the mean from it and divide by the standard deviation:

(X-X[bar])/S= (36-74)/12.5= -3.04

The minimum pulse for female adults is -3.04 standard deviations away from the mean.

c)

The z score for 36 beats/min is -3.04

Considering the region of acceptance (-2; 2), the calculated value is below its lower limit, so you can conclude that the pulse rate 36 beats/min is significantly low.

I hope this helps!

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

10

step-by-step explanation: