The life cycle of a darkling beetle is shown here. Which stage represents the change from larva to adult?

D

Step-by-step explanation:

The diagramatic representation of the life cycle of a darkling beetle is shown in the attached file below.

The metamorphosis of the darkling bettle takes four stages:

egg → larva → pupa→ adult

After laying the eggs by an adult darkling bettle, the eggs are encased in a fluid-like covering to prevent it from damage as a result of environmental factors. The egg metamorphosize into the larva stage; a period of feeding and growth. They then in turn proceed into the pupa stage where they are being enclosed in a cocoon. In the cocoon, they undergo modifications and become sexually matured before they enters into adulthood.

Thus, the stage that represent the change fromm larva to adult is the pupa stage and it is shown in the diagram as option D

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

~