The price of a rare collection car has increased exponentially over the past few years with a rate of increase estimated at 5% per year.
At the start of 2015 the value of the car was estimated at £265000.
Estimate the value of the car at the start of 2010.
Round your answer to 3 significant figures.

£208,000

Step-by-step explanation:

Hi, to answer this question we have to apply an exponential growth function:

A = P (1 + r) t  

Where:

p = original price

r = increase rate (decimal form)

t= years  (2015-2010 =5 years)

A = price after t years

Replacing with the values given:

265,000 = p (1+ 0.05)^5

Solving for p

265,000 = p (1.05)^5

265,000 = p (1.05)^5

265,000/ (1.05)^5 =p

p =  £207,634. =208,000 (rounded)

Feel free to ask for more if needed or if you did not understand something.

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.