The length of a rectangle is twice as long as the width. If the diagonal length of the rectangle is 60 cm, what is the perimeter of the rectangle (to the nearest centimetre)?
Provide a complete algebraic solution, including a supporting diagram.
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And we can find the perimeter as:

And replacing the value given for x we got:

And for this case the perimeter would be approximately

Step-by-step explanation:

For this case we can assume that the lenght is 2x the width x and the diagonal is 60 cm.

From the picture given we have a right tirngle and we can set the following equation:

And solving for x we got:

And we can find the perimeter as:

And replacing the value given for x we got:

And for this case the perimeter would be approximately

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i ran through it by the other answer is wrong