What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (-2,4)? Y=-5/2x-1

y=-5/2x+5

y=2/5x-1

Y=2/5x+5

y=-5/2x-1

Step-by-step explanation:

change the equation to slope intercept form

y=-5/2x+6

graph the point (-2, 4)

use the slope of the equation to find the y intercept

y intercept = -1

write equation of the parallel line using the same slope of the first line

-5/2x

and the y intercept of the new parallel line -1

y=-5/2x-1

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3