Mathematics, 04.06.2020 13:25, Clover1072
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6965 subjects randomly selected from an online group involved with ears. There were 1330 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. A. Upper H 0: pequals0.2 Upper H 1: pless than0.2 B. Upper H 0: pgreater than0.2 Upper H 1: pequals0.2 C. Upper H 0: pequals0.2 Upper H 1: pnot equals0.2 D. Upper H 0: pnot equals0.2 Upper H 1: pequals0.2 E. Upper H 0: pless than0.2 Upper H 1: pequals0.2 F. Upper H 0: pequals0.2 Upper H 1: pgreater than0.2 The test statistic is zequals nothing. (Round to two decimal places as needed.) The P-value is nothing. (Round to three decimal places as needed.) Because the P-value is
Answers: 3
Mathematics, 21.06.2019 17:00, beautycutieforever10
Evaluate the expression for the given value of the variable. 5×(h+3) for h=7
Answers: 1
In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6...
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