An isosceles triangle has a base whose length is 14 centimeters and whose base angle each measure 68

I guess you want to find the lenght of the sides and the other angle, so let's do that:

We know that the base has a length of 14 cm.

The two base angles are 68°

First, we can find the other angle knowing that the sum of all interior angles of a triangle must add up to 180°.

2*68° + X = 180°

X = 180° - 2*68° = 44°

Now let's find the length of the sides (that is the same for both sides, as we have an isosceles triangle.

For this we can draw a line for the middle of the base that goes through the top vertex, creating in this way a triangle rectangle.

We know that one of the cathetus will have half of the length of the base, this is 7cm.

the adjacent angle to this cathetus is 68°, now we want to find the hypotenuse of this triangle, we can use the relation:

Cos(A) = adjacent cathetus/hypotenuse:

Cos(68°) = 7cm/H

H = 7cm/cos(68) = 18.7cm

this hypotenuse is equal to the side length of our isosceles triangle, so now we have it fully determined.

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's

7

step-by-step explanation:

the answer would be 7