Data was collected for 226 randomly collected 10 minute interval. For each Tim and I are in a rule the number of people entering the atrium of a large mall were recorded. The data is summarized in the table below What is the width for this GFDT?

Number of guest. Frequency

60-64. 57

65-69. 39

70-74. 7

75-79. 36

80-84. 87

The class width of this grouped frequency distribution (GFDT) = 5.

The total width of the distribution = 25, that is, from 60 to 84.

Step-by-step explanation:

The class width of a GFDT (grouped frequency distribution) is obtained by dividing the range by the number of classes required and then rounding up.

Note that rounding up is different from rounding off as 4.2 is rounded up to 5 and rounded off to 4.

The class width is the span of each of the class in the grouped frequency distribution.

For this distribution,

Maximum value = 84

Minimum value = 60

Range = (Maximum value) - (Minimum value) = 84 - 60 = 24

Number of classes required = 5

Class width = (24/5) = 4.8 = 5 (rounded up).

The total width of the distribution is given as

Total width = Range + 1 = 24 + 1 = 25.

Hope this Helps!!!

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

12.5 feet

step-by-step explanation: