Write an equation of the line that passes through the point (4,7) that is parallel to the line y = 3x+1

Explanation:

The given line y = 3x+1 has a slope of 3 as it is in the form y = mx+b

Any line parallel to this given line will also have a slope of 3. Parallel lines have equal slopes but different y intercepts.

Using m = 3 and (x,y) = (4,7), find the value of b

y = mx+b

7 = 3*4+b

7 = 12+b

12+b = 7

b = 7-12

b = -5

We have y = mx+b update to y = 3x+(-5) or y = 3x-5

Plug in x = 4 and you'll have y = 3x-5 turn into y = 7.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18