Which of the following closed sets of ordered pairs is not a function?

A
{(3, 2), (4, 6), (5, 8)}

B
{(2, 1), (3, 2), (4, 3)}

C
{(1, 2), (2, 5), (1, 3)}

D
{(2, 4), (5, 3), (4, 1)}

C

Step-by-step explanation:

A function cannot have overlapping x-coordinates

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

the answer is d

hope this