Consider random samples of size 40 from a population with proportion 0.15.
(a) Find the standard error of the distribution of sample proportions.
Round your answer for the standard error to three decimal places.
mean=
standard error=
(b) Is the sample size large enough for the Central Limit Theorem to apply?
1. Yes
2. No

The standard error of the distribution of sample proportions is 0.056 and mean is 0.15.

Yes, the sample size is enough for the Central Limit Theorem to apply.

(a). Given that, size of sample,

        Proportion,

In the distribution of sample proportions, mean  

and, standard error =

So, mean

Standard error =

(b). The Central Limit Theorem applies if np > 5 .

Thus, the Central Limit Theorem is applied.

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a) The mean is 0.15 and the standard error is 0.056.

b)  1. Yes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions p, in samples of size n, the mean is and the standard error is . The Central Limit Theorem applies is np > 5 and np(1-p)>5.

In this question:

So

(a) Find the mean and the standard error of the distribution of sample proportions.

So the mean is 0.15 and the standard error is 0.056.

(b) Is the sample size large enough for the Central Limit Theorem to apply?

np = 40*0.15 = 6 > 5

np(1-p) = 40*0.15*0.85 = 5.1>5

So yes

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step-by-step explanation:

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it