A cooler contains ten bottles of sports drink: four lemon-lime flavored, three orange-flavored, and three fruit-punch flavored. Three times, you randomly grab a bottle, return the bottle to the cooler, and then mix up the bottles. The first time, you get a lemon-lime drink. The second and third times, you get fruit-punch.

show work please thanks! 20 poin!!

The probability is 0.036

Step-by-step explanation:

We have a total of 10 sports drinks.

4 lemon-lime

3 orange

3 fruit-punch.

in the first draw, we pick a lemon-lime drink.

The probability of this is equal to the number of lemon-lime drinks divided by the total number of drinks: p1 = 4/10.

Then we return it and we mix the drinks.

In the second time, we draw a fruit-punch one, so now the probability is:

p2 = 3/10

We return the drink.

For the third time we again pick a fruit-punch.

Again, we have p3 = 3/10.

Now for the joint probability of the 3 events we must multiplcate the individual probabilities, this is:

P = p1*p2*p3 = (4/10)*(3/10)*(3/10) = 36/100 = 0.036

can you post the graph?