The average mark of candidate in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are 148, 102,152. What is the average of the extracted scores t hat are extreme values (outliers)?

Step-by-step explanation:

Given that  : The average marks of candidates in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are; 148, 102 and 152.

The objective here is to determine the average of the extracted scores that are the extreme values (outliers)

NOW:

The average marks of candidates in an aptitude test was 128.5

i.e the Mean = 128.5

Standard Deviation = 8.2

outlier will be outsides;

then the range  will be    Mean  ± 3 × SD

= 128.5 ± 8.2 × 3

= 128.5 ± 24.6

Range is  ( 103.9  ,  153.1)

102 is outside this range

Hence, the average of the extracted scores that are extreme values (outliers) will be 102 only

answer: city needs 2.4 inches of rainfall more to match the record of 40 inches.

step-by-step explanation:

since we have given that

total annual rainfall a city record = 40 inches

this year, total rainfall recorded = 37.6 inches

number of inches of rainfall   is needed to match the record of 40 inches is given by

hence, city needs 2.4 inches of rainfall more to match the record of 40 inches.

i believe the answer is letter c) 8

step-by-step explanation: