A parabola has a y-intercept of 4 and passes through points (2, 8)
and (1, 1). Determine the vertex of the parabola. WHOEVER ANSWERS RIGHT GETS BRAINLIEST!

The vertex happens at ()

Step-by-step explanation:

First of all, we know that the y - intercept is 4, this gives us a third point which is (0,4)

We know that the equation of the parabola: y = .

We also have three points, this means we will end up with three equations and therefore, we would need to solve for A, B and C.

First equation: 4 = A(0) +B(0) + C , C= 4

Second equation: 8 = A(2)^2 + B(2) + 4,

8 = 4A + 2B + 4

4 = 4A + 2 B (Now we need to divide by 4)

1 = A + B where A = 1 - 0.5B

Third equation: 1 = A(1) + B(1) + 4, we know A = 1 -0.5 B so we can substitute it and solve for B.

-3 =1 -0.5(b) + B, We get b = -8

We also figured out that A = 1 - 0.5B and b = -8, therefore A = 5.

Therefore, the equation of the parabola is y =

In order to find the vertex, we take the derivative and equate it to 0.

y' = 10x -8= 0,

x =

Now we now the x-coordinate of the vertex, in order to find the y-coordinate we have to substitute it into the equation.

y = ,

therefore, y = .

Therefore, the vertex is at the point

Great question, haven't done these since highschool had to look up some stuff.

Hope this helps.

d) 48

step-by-step explanation:

16,32,48,64,80,96,112,128,144,160,176,192,208,224,240,256,272,288,304,320,336