The endpoints of segment TU are T(-8, 4) and U(6, -1). Calculate the coordinates of the midpoint, M. *

The point M(Mx, My) is mid-point of TU with T(Tx, Ty) and U(Ux, Uy).

=> 2*Mx = Tx + Ux => 2*Mx = -8 + 6 => Mx = -1

=> 2*My = Ty + Uy => 2*My = 4 + (-1) => My = 3/2

=> M(-1, 3/2)

Hope this helps!

:)

answer:

your answer is: c. 196 7/8 in^3.

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )