A) Find the difference between3y minutes and 25y second, giving your answer in second.
B) find the sum of 50(3z- 2) minutes and4(z+1) hour, giving your answer in second.
Pls tell answers of both question

155ysec ; 23400z+ 8400 secs

Step-by-step explanation:

3y mins = 3* 60=180y sec

3y mins - 25y sec= 180y sec - 25y= 155y sec

155ysec

From B

50(3z-2)min = 50 * 60 (3z-2) sec

= 3000(3z-2)=9000z-6000

4 (z + 1) hours =4*3600(z+1) =14400z + 14400z

Adding both expression we have;

9000z+14400z-6000+14400=23400z+ 8400 secs

23400z+ 8400 secs

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

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